Let a, b, c, d be no zero numbers. If the point of intersection of the line 4ax + 2ay + c = 0 & 5bx + 2by + d=0 lies in the fourth quadrant and is equidistance from the two are then
The lines px+qy=1 and qx+py=1 are respectively the sides AB, AC of the triangle ABC and the base BC is bisected at (p,q). Equation of the median of the triangle through the vertex A is